目录

力扣685. 冗余连接 II

力扣685. Redundant Connection II(冗余连接 II)

找到有向树中可删除的一条边。

示例 1:

../posts/01_学习/87_LeetCode/0685_冗余连接II/img/0685-1-description.png

输入:[[1,2],[1,3],[2,3]]
输出:[2,3]

提示:

  • n == edges.length
  • 3 <= n <= 1000
  • edges[i].length == 2
  • 1 <= ai, bi <= n