目录

力扣79. 单词搜索

力扣79. Word Search(单词搜索)

给定一个 m×n 二维字符网格 board 和一个字符串单词 word。如果 word 存在于网格中,返回 true;否则返回 false。单词必须按照字母顺序,通过相邻的单元格内的字母构成,其中相邻单元格是那些水平相邻或垂直相邻的单元格。同一个单元格内的字母不允许被重复使用。

示例 1:

../posts/01_学习/87_LeetCode/0079_单词搜索/img/0079-1-description.png

输入:board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "ABCCED"
输出:true

示例 2:

输入:board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "SEE"
输出:true

示例 3:

输入:board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "ABCB"
输出:false

提示:

  • m == board.length
  • n == board[i].length
  • 1 <= m, n <= 6
  • 1 <= word.length <= 15
  • board 和 word 仅由大小写英文字母组成